http://aolanswers.com/questions/factor-difference-two-cubes-x-3-64_518417303038146/notice-64-4-3-nbsp-follow-rule-b-2_735402187135006?src=rss:qbp:qpbs<p>All you have to do is <span style="text-decoration:underline;">notice</span> that 64 = 4^3  <br/>Now it will follow the rule (a^3 - b^3) = (a - b) * (a^2 +ab + b^2) <br/>So, in your case:  <br/><strong>(x^3 -64) = (x-4) * (x^2 +4x + 4^2)</strong></p> <p> </p>en-ushttp://s1.anscdn.net/images/answers/aolanswerslogo_rmtaac1f83.gifhttp://aolanswers.com/questions/factor-difference-two-cubes-x-3-64_518417303038146/notice-64-4-3-nbsp-follow-rule-b-2_735402187135006?src=rss:qbp:qpbs<p>All you have to do is <span style="text-decoration:underline;">notice</span> that 64 = 4^3  <br/>Now it will follow the rule (a^3 - b^3) = (a - b) * (a^2 +ab + b^2) <br/>So, in your case:  <br/><strong>(x^3 -64) = (x-4) * (x^2 +4x + 4^2)</strong></p> <p> </p>http://aolanswers.com/questions/factor-difference-two-cubes-x-3-64_518417303038146/notice-64-4-3-nbsp-follow-rule-b-2_735402187135006?src=rss:qbp:qbpi<p>All you have to do is <span style="text-decoration:underline;">notice</span> that 64 = 4^3  <br/>Now it will follow the rule (a^3 - b^3) = (a - b) * (a^2 +ab + b^2) <br/>So, in your case:  <br/><strong>(x^3 -64) = (x-4) * (x^2 +4x + 4^2)</strong></p> <p> </p>OronDOronDmale113answer4.0Fri, 09 Mar 2012 04:58:26 GMThttp://aolanswers.com/questions/factor-difference-two-cubes-x-3-64_518417303038146/notice-64-4-3-nbsp-follow-rule-b-2_735402187135006?src=rss:qbp:qbpi